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प्र: RADAR is used for 1928 0

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    detecting and locating the position of objects such as Aeroplanes
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    locating submerged submarines
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    locating geostationary satellites
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    receiving a signals in a radio receiver
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उत्तर : 1. "detecting and locating the position of objects such as Aeroplanes"
व्याख्या :

Answer: A) detecting and locating the position of objects such as Aeroplanes Explanation: RADAR - RAdio Detection And Ranging. A radar system consists of a transmitter producing electromagnetic waves in the radio or microwaves domain, a transmitting antenna, a receiving antenna (often the same antenna is used for transmitting and receiving) and a receiver and processor to determine properties of the objects.    Radar is an object-detection system that uses radio waves to determine the range, angle, or velocity of objects. It can be used to detect aircraft, ships, spacecraft, guided missiles, motor vehicles, weather formations, and terrain.   Radio waves from the transmitter reflect off the object and return to the receiver, giving information about the object's location and speed.

प्र: There is sufficient salary to give K for 10 days and L for 15 days. Then how many days will the money last if both has to be given the salary ? 1928 0

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    6 days
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    12 days
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    4 days
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    9 days
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उत्तर : 1. "6 days"
व्याख्या :

Answer: A) 6 days Explanation: K's 1 day's salary = 1/10 L's 1 day's salary = 1/15 Together their 1 day's salary = 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6 So the money will be enough for paying them both for 6 days.

प्र: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 1928 0

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    Rs. 1,24,000
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    Rs. 1,44,000
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    Rs. 1,32,000
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    Rs. 1,62,000
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उत्तर : 2. "Rs. 1,44,000"
व्याख्या :

Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.

प्र: 20 men went to a restaurant. Ninteen of them paid Rs.70 each and the twentieth man paid Rs.90.25 more than the average of all the 20 men. What is the total bill ? 1928 0

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    Rs. 1495
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    Rs. 548
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    Rs. 850
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    Rs. 1750
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उत्तर : 1. "Rs. 1495"
व्याख्या :

Answer: A) Rs. 1495 Explanation: Let the average bill paid by twenty members = 'x' But 19 men paid each = Rs. 70 20th man paid Rs. 90.25 more than the avg bill of 20 = x + 90.25 20x = 19(70) + x + 90.2519x = 1330 + 90.2519x = 1420.25x = 1420.25/19 = Rs. 74.75 But the total bill = 20 x 74.75 = Rs. 1495.

प्र: What has no beginning, end or middle? 1928 0

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उत्तर :
व्याख्या :

A Donut or Doughnut. Anything in the shape of a torus.

प्र: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most  ? 1927 0

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    215
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    268
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    254
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    216
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उत्तर : 1. "215"
व्याख्या :

Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt.   Maximum number of unsuccessful attempts = 216 - 1 = 215.

प्र: The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ? 1925 0

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    87
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    81
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    83
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    85
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उत्तर : 1. "87"
व्याख्या :

Answer: A) 87 Explanation: Cp1 = p2 - p1 , Cp2 = p3 - p2 ......Cp23 = p24 - p23Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)All terms get cancelled, except p1 = 2 and p24 = 89 So Sum = -p1 + p24Sum of series = -2 + 89 = 87

प्र: How many seconds in 10 years? 1923 0

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    31523500 sec
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    315360000 sec
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    315423000 sec
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    315354000 sec
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उत्तर : 2. "315360000 sec"
व्याख्या :

Answer: B) 315360000 sec Explanation: We know that, 1 year = 365 days 1 day = 24 hours 1 hour = 60 minutes 1 minute = 60 seconds.   Then, 1 year = 365 x 24 x 60 x 60 seconds. = 8760 x 3600 1 year = 31536000 seconds.   Hence, 10 years = 31536000 x 10 = 315360000 seconds.

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