GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction ? 1548 05b5cc6e2e4d2b4197774ec2f
5b5cc6e2e4d2b4197774ec2f- 158 secfalse
- 262 secfalse
- 360 secfalse
- 450 sectrue
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उत्तर : 4. "50 sec"
व्याख्या :
Answer: D) 50 sec Explanation: The distance to be covered = Sum of their lengths = 200 + 300 = 500 m. Relative speed = 72 -36 = 36 kmph = 36 x 5/18 = 10 mps. Time required = d/s = 500/10 = 50 sec.
प्र: The area of a square is 1024 sq.cm. What is the ratio of the length to the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of this square ? 1547 05b5cc72ce4d2b4197774f76e
5b5cc72ce4d2b4197774f76e- 114:9false
- 213:12false
- 316:5true
- 417:13false
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उत्तर : 3. "16:5"
व्याख्या :
Answer: C) 16:5 Explanation: Area of a square SxS = 1024 => S = 32 cmLength of the rectangle = 32x2 cm = 64 cmBreadth of the rectangle = 32 - 12 = 20 cmRequired ratio = 64 : 20 = 16 : 5
प्र: Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ? 1546 05b5cc6c5e4d2b4197774ddb9
5b5cc6c5e4d2b4197774ddb9- 1Rs.6000false
- 2Rs.4500false
- 3Rs.7500false
- 4Rs.5000true
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उत्तर : 4. "Rs.5000"
व्याख्या :
Answer: D) Rs.5000 Explanation: Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then, As we know: Simple interest (S.I.) = PTR/100 (a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200 = 10a + 12b + 15c = 320000 .........(1) Now, c = 240% of b = 12b/5 .........(2) And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3) From (1), (2) and (3), we have 16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000 ∴ Sum invested in Scheme Y = Rs.5000.
प्र: Math Logic Challenge 1546 05b5cc6d3e4d2b4197774e4b4
5b5cc6d3e4d2b4197774e4b4- 123false
- 226true
- 313false
- 429false
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उत्तर : 2. "26"
व्याख्या :
Answer: B) 26 Explanation: Let the integer be x. Then, x2-20x = 156 (x + 6)(x - 26) = 0 x = 26 The integer is 26.
प्र: 100 percent of which number is 20? 1546 05b5cc6b0e4d2b4197774d28d
5b5cc6b0e4d2b4197774d28d- 1100false
- 2500false
- 320true
- 40false
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उत्तर : 3. "20"
व्याख्या :
Answer: C) 20 Explanation: Let the rquired number be 'P' According to the question, 100 x P100 = 20=> P = 20 x 100100 = 20 Hence, 100 percent of the number 20 is 20. Now, you can also try for 20 percent of what number is 100 20 x P100 = 100=> P = 100 x 10020 = 500=> P = 500 Hence, 20 percent of the number 500 is 100.
प्र: Which of these illustrates the Secondary Structure of a Protein? 1545 05b5cc6abe4d2b4197774d02a
5b5cc6abe4d2b4197774d02a- 1Afalse
- 2Btrue
- 3Cfalse
- 4Dfalse
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उत्तर : 2. "B"
व्याख्या :
Answer: B) B Explanation: The Secondary Structure of a Protein is option B) The Secondary Structure of a Protein results from Hydrogen Bonds.
प्र: A person lends Rs. 1540 for five years and Rs. 1800 for four years. If he gets Rs. 1788 as interest on both amounts, what is the rate of interest ? 1542 05b5cc6c8e4d2b4197774deec
5b5cc6c8e4d2b4197774deec- 114.5%false
- 211%false
- 312%true
- 410.5%false
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उत्तर : 3. "12%"
व्याख्या :
Answer: C) 12% Explanation: Let the interest rate be r% We know that, S.I = PTR/100 => (1540 x 5 x r)/100 + (1800 x 4 x r)/100 = 1788 => r = 178800/14900 = 12%
प्र: 5 + 2 x 10 = 1541 05b5cc622e4d2b4197774b7e9
5b5cc622e4d2b4197774b7e9- 170false
- 220false
- 325true
- 452false
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उत्तर : 3. "25"
व्याख्या :
Answer: C) 25 Explanation: According to BODMAS rule, After multiplication only, addition is done. Hence, 5 + 2 x 10 = 5 + 20 = 25.

