IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: If the labour cost 20% of the cost of production and raw material cost 10% of the cost of production and the price on which article is sold is 20% above the cost of production. If the price of labour is increased by 40% and the price of raw material increased by 20% and rest other expenditure of cost remain constant. The industry thus decide to increase the selling price by 10%. Find the new profit percent ? 1891 05b5cc6c7e4d2b4197774de78
5b5cc6c7e4d2b4197774de78- 118%false
- 220%true
- 322%false
- 424%false
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उत्तर : 2. "20%"
व्याख्या :
Answer: B) 20% Explanation: Let the Cost of Production of the article = 100 Then, Labour Cost = 20 Raw Material = 10 Other Expenditure = 100 - 10 – 20 = 70 Selling Price of the article = 120 After increasing Labour and Raw material cost by 40% & 20% respectively, New Labour cost = 28 New Raw material cost = 12 New Cost of Production = 70 + 28 + 12 = 110 Then, New SP = 110% of 120 = 120 x 110/100 = 132 => New Gain = 132 - 110 = 22 => New Profit % = 22 x 100/110 = 20%
प्र: Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ? 1999 05b5cc6c7e4d2b4197774de6e
5b5cc6c7e4d2b4197774de6e- 1108false
- 2107false
- 3109true
- 4110false
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उत्तर : 3. "109"
व्याख्या :
Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109
प्र: P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ? 2192 05b5cc6c7e4d2b4197774de73
5b5cc6c7e4d2b4197774de73- 199true
- 2100false
- 389false
- 41false
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उत्तर : 1. "99"
व्याख्या :
Answer: A) 99 Explanation: Let, Distance between A and B = d Distance travelled by P while it meets Q = d + 11 Distance travelled by Q while it meets P = d – 11 Distance travelled by Q while it meets R = d + 9 Distance travelled by R while it meets Q = d – 9 Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11 The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9 But given Ratio of speeds of P & R => P : R = 3 : 2 SPSR = SPSQxSQSR = d+11d+9d-11d-9 => d+11d+9d-11d-9 = 3/2 => d = 1, 99 => d = 99 satisfies. Therefore, Distance between A and B = 99
प्र: Which Country has opened its fifth Nuclear Power Plant to meet its growing energy demands ? 2626 05b5cc6c6e4d2b4197774de63
5b5cc6c6e4d2b4197774de63- 1Indiafalse
- 2Pakistantrue
- 3Russiafalse
- 4Chinafalse
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उत्तर : 2. "Pakistan"
व्याख्या :
Answer: B) Pakistan Explanation:
प्र: In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ? 1393 05b5cc6c6e4d2b4197774de5e
5b5cc6c6e4d2b4197774de5e- 12:3false
- 24:3false
- 33:4false
- 43:2true
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उत्तर : 4. "3:2"
व्याख्या :
Answer: D) 3:2 Explanation: Let he mixes the oils in the ratio = x : y Then, the cost price of the oils = 60x + 65y Given selling price = Rs. 68.20 => Selling price = 68.20(x+y) Given profit = 10% = SP - CP => 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y) => 6x + 6.5y = 8.20x + 3.20y =>2.2x = 3.3y => x : y = 3 : 2
प्र: The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ? 2922 05b5cc6c6e4d2b4197774de59
5b5cc6c6e4d2b4197774de59- 112 yearstrue
- 210 yearsfalse
- 314 yearsfalse
- 413 yearsfalse
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उत्तर : 1. "12 years"
व्याख्या :
Answer: A) 12 years Explanation: Given the average age of couple and their son = 40 => Sum of age (H +W +S) = 40×3 Let the age of daughter in law at the time of marriage = D years Now after 10 years, (H + S +W) + 3×12 + D +12 + 10 = 38×5 178 + D = 190 D = 190 -178 = 12 years
प्र: If two line pa + b = 2 and 3a + b = 4 are parallel to each other, then what is the value of p ? 1393 05b5cc6c6e4d2b4197774de54
5b5cc6c6e4d2b4197774de54- 11false
- 22false
- 33true
- 44false
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उत्तर : 3. "3"
व्याख्या :
Answer: C) 3 Explanation: Given two lines are parallel pa+b=2 b=-pa+2..........(1) 3a+b=4 b=-3a+4 ...........(2) m1 = -p m2= -3 The condition for the two lines to be parallel is m1=m2 p = 3
प्र: In a row of boys, Haran is eleventh from the left and manoj is seventeenth form the right. When they exchange their places than Haran will be thirteenth from the left. Which of the following will be the new position of Manoj from the right ? 3707 05b5cc6c6e4d2b4197774de4f
5b5cc6c6e4d2b4197774de4f- 111false
- 219true
- 313false
- 417false
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उत्तर : 2. "19"
व्याख्या :
Answer: B) 19 Explanation: Here total number of boys in the row = 11 + 19 = 13 + 17 = 30 Here after exchanging the places of Haran & Manoj => Manoj replaces Harans place of 11th from left But in the question he asked Manoj's place from right = 30 - 11 = 19th place.