Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the missing number in the series 1, 6, ?, 15, 45, 66, 91 2715 15b5cc6afe4d2b4197774d230
5b5cc6afe4d2b4197774d230- 124false
- 228true
- 332false
- 426false
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उत्तर : 2. "28"
व्याख्या :
Answer: B) 28 Explanation: Here the given series 1, 6, ?, 15, 45, 66, 91 follows a Pattern in the series is, +5, +9, +13,...,.. +21, +25 So +4 is getting increased at every term addition. Missing Number in the series will be 15+(9+4) = 15 + 13 = 28.
प्र: Simplify 413 + 215 + 414 = ? 1351 05b5cc6afe4d2b4197774d235
5b5cc6afe4d2b4197774d235- 110 47/60true
- 211 45/73false
- 311 47/36false
- 410 35/48false
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उत्तर : 1. "10 47/60"
व्याख्या :
Answer: A) 10 47/60 Explanation: The given equation is in Mixed fraction. Now to solve this type of fractions, 413 + 215 + 414 =?? = 4 + 2 + 4 + 13 + 15 + 14 ? = 10 + 4760? = 104760
प्र: Fresh grapes contain 60% water, while dry grapes contain 40% water. How many kgs of dry grapes can be obtained by 60 kg of fresh grapes? 3957 05b5cc6afe4d2b4197774d1e2
5b5cc6afe4d2b4197774d1e2- 125 kgsfalse
- 230 kgsfalse
- 335 kgsfalse
- 440 kgstrue
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उत्तर : 4. "40 kgs"
व्याख्या :
Answer: D) 40 kgs Explanation: The fruit content in both the fresh fruit and dry fruit is the same. Let 'p' kgs of dry grapes are obtained from the 60 kgs of fresh grapes => 60 x 40100 = p x 60100=> p = 40 kgs. Therefore, 40 kgs of Dry grapes are obtained from 60 kgs of Fresh grapes.
प्र: A motorboat takes half time to cover a certain distance downstream than upstream. What is the ratio between rate of current and rate of boat in still water? 1925 05b5cc6afe4d2b4197774d1e7
5b5cc6afe4d2b4197774d1e7- 11 : 3true
- 23 : 2false
- 32 : 3false
- 43 : 1false
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उत्तर : 1. "1 : 3"
व्याख्या :
Answer: A) 1 : 3 Explanation: Let the speed of the boat in still water is 'w' Speed of the current is 'c' Let the distance between two places is 'd' According to the question, motorboat takes half time to cover a certain distance downstream than upstream. dw+c = 12dw-c => 2w - 2c = w + c => w = 3c => c : w = 1 : 3 Hence, the ratio between rate of current(c) and rate of boat in still water(w) = 1 : 3
प्र: How many days in 4 years? 1901 05b5cc6aee4d2b4197774d1a1
5b5cc6aee4d2b4197774d1a1- 11460true
- 21461false
- 31462false
- 41459false
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उत्तर : 1. "1460"
व्याख्या :
Answer: A) 1460 Explanation: Days in 4 years => Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years. 4 years => 365 + 365 + 365 + 366(Leap year) 4 years => 730 + 731 = 1461 Therefore, Number of Days in 4 Years = 1461 Days.
प्र: In order to maximize his gain, a shopping mall owner decides to reduce the price of electronics goods by 20% and as a result of this, the sales of electronics increase by 40%. If, as a result of these changes, he is able to increase his weekly collection by Rs. 1,05,000, find by what value did the gross collection increase per day? 4790 05b5cc6aee4d2b4197774d188
5b5cc6aee4d2b4197774d188- 1Rs. 14400false
- 2Rs. 14600false
- 3Rs. 14800false
- 4Rs. 15000true
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उत्तर : 4. "Rs. 15000"
व्याख्या :
Answer: D) Rs. 15000 Explanation: It won't requires that much solving. Here given the increase in weekly collection by Rs. 1,05,000 That is this increase denotes for all 7 days. => Gross Collection increase per day = Rs. 1,05,0007 = Rs. 15,000 Hence, the gross collection increase per day = Rs. 15,000.
प्र: An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%? 1603 05b5cc6aee4d2b4197774d179
5b5cc6aee4d2b4197774d179- 145 gmfalse
- 250 gmtrue
- 355 gmfalse
- 460 gmfalse
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उत्तर : 2. "50 gm"
व्याख्या :
Answer: B) 50 gm Explanation: Initial quantity of copper =80100 x 50 = 40 g And that of Bronze = 50 - 40 = 10 g Let 'p' gm of copper is added to the mixture => 50 + p x 90100 = 40 + p => 45 + 0.9p = 40 + p => p = 50 g Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.
प्र: There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number? 1947 05b5cc6aee4d2b4197774d165
5b5cc6aee4d2b4197774d165- 129true
- 227false
- 331false
- 433false
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उत्तर : 1. "29"
व्याख्या :
Answer: A) 29 Explanation: Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4 According to the question, Difference between square of the average of first two odd number and the of the average last two odd numbers is 396 i.e, x+3 and x-3 ⇒x + 32 - x - 32 = 396⇒ x2 + 9 + 6x - x2 + 6x - 9 = 396⇒ 12x = 396⇒ x = 33 Hence, the smallest odd number is 33 - 4 = 29.

