Quantitative Aptitude Practice Question and Answer
8Q: The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is 1858 05b5cc6d9e4d2b4197774e80c
5b5cc6d9e4d2b4197774e80c- 1196 mtsfalse
- 2220 mtsfalse
- 3230 mtsfalse
- 4245 mtstrue
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Answer : 4. "245 mts"
Explanation :
Answer: D) 245 mts Explanation: Let the length of the brigade is x mtsThen Distance = 130 + x mtsgiven speed = 45 kmph = 45 x5/18 m/sTime = 30 secT = D/S => 30 = 130+x/(45x5/18)=> x = 245 mts.
Q: The average of marks in 3 subjects is 224. The first subject marks is twice the second and the second subject marks is twice the third. Find the second subject marks ? 1858 05b5cc6cce4d2b4197774e17c
5b5cc6cce4d2b4197774e17c- 1384false
- 296false
- 3192true
- 4206false
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Answer : 3. "192"
Explanation :
Answer: C) 192 Explanation: Let the third subject marks be 'x'=> Second subject marks = 2x=> Third subject marks = 4xGiven avg = 224x + 2x + 4x = 224 x 3=> 7x = 224 x 3=> x = 96Hence, Second subject marks = 2x = 2 x 96 = 192.
Q: In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ? 1857 05b5cc74fe4d2b4197774faf4
5b5cc74fe4d2b4197774faf4- 125 mtrue
- 221 mfalse
- 322 mfalse
- 419 mfalse
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Answer : 1. "25 m"
Explanation :
Answer: A) 25 m Explanation: A:B = 200 : 169A:C = 200 : 182 CB = CA×AB 182200×200169 => 182:169 When C covers 182 m , B Covers 169 mWhen C covers 350 m , B Covers 169182×350=> 325 m So C beats B by (350 - 325) = 25 m.
Q: When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ? 1854 05b5cc736e4d2b4197774f88d
5b5cc736e4d2b4197774f88d- 122false
- 236true
- 332false
- 426false
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Answer : 2. "36"
Explanation :
Answer: B) 36 Explanation: Total number of students = 54 x 30When arranged in rows of 45, number of rows formed are, 54x3045 = 36.
Q: Two trains of equal length are running on parallel lines in the same direction at 36 km/hr and 26 km/hr. The faster train passes the slower train in 36 sec. The length of each train is ? 1852 05b5cc6e0e4d2b4197774eb93
5b5cc6e0e4d2b4197774eb93- 128 mtsfalse
- 254 mtsfalse
- 324 mtsfalse
- 450 mtstrue
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Answer : 4. "50 mts"
Explanation :
Answer: D) 50 mts Explanation: Let the length of each train be x mts. Then, distance covered = 2x mts. Relative speed = 36 - 26 = 10 km/hr. = 10 x 5/18 = 25/9 m/sec. 2x/36 = 25/9 => x = 50 mts.
Q: An express traveled at an average speed of 100 km/hr, stopping for 4 min after every 75 km. How long did it take to reach its destination 600 km from the starting point ? 1852 05b5cc6e1e4d2b4197774eba7
5b5cc6e1e4d2b4197774eba7- 16 hrs 24 minfalse
- 26 hrsfalse
- 37 hrs 21 minfalse
- 46 hrs 28 mintrue
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Answer : 4. "6 hrs 28 min"
Explanation :
Answer: D) 6 hrs 28 min Explanation: Time taken to cover 600 km = 600/100 = 6 hrs. Number of stoppages = 600/75 - 1 = 7 Total time of stoppages = 4 x 7 = 28 min Hence, total time taken = 6 hrs 28 min.
Q: What should come in place of question mark (?) in the following number series? 38, 195, ?, 4905, 24530, 122655 1850 05b5cc6c4e4d2b4197774dcd2
5b5cc6c4e4d2b4197774dcd2- 1980true
- 2885false
- 3824false
- 41021false
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Answer : 1. "980"
Explanation :
Answer: A) 980 Explanation: The given series follows the pattern that, ×5+5, ×5+5, ×5+5, ×5+5, ×5+5 38 x 5 + 5 = 195 195 x 5 + 5 = 980 980 x 5 + 5 = 4905 4905 x 5 + 5 = 24530 24530 x 5 + 5 = 122655 So the missing number is 980 .
Q: Consider 5 independent Bernoulli’s trials each with probability of success p. If the probability of at least one failure is greater than or equal to 31/32 , then p lies in the interval ? 1850 05b5cc71ee4d2b4197774f5c7
5b5cc71ee4d2b4197774f5c7- 1[1, 32]false
- 2(0, 1)false
- 3[1, 1/2]true
- 4(1, 1/2]false
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Answer : 3. "[1, 1/2]"
Explanation :
Answer: C) [1, 1/2] Explanation: Probability of atleast one failure= 1 - no failure > 31/32= 1 - P5 > 31/32= P5<1/32= p < 1/2Also p > 0Hence p lies in [0,1/2].