Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type ? 5806 05b5cc77fe4d2b4197775017e
5b5cc77fe4d2b4197775017e- 126true
- 224false
- 318false
- 412false
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उत्तर : 1. "26"
व्याख्या :
Answer: A) 26 Explanation: Gold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600 Find a number which exactly divide all these numbers That is HCF of 18000, 9600& 3600 All the value has 00 at end so the factor will also have 00. HCF for 180, 96 & 36. Factors of 180 = 3 x 3 x 5 x 2 x 2 96 = 2 x 2 x 2 x 2 x 2 x 3 36 = 2 x 2 x 3 x 3 Common factors are 2x2×3=12 Therefore, Actual HCF is 1200 Gold Coins 18000/1200 will be in 15 rooms Silver Coins 9600/1200 will be in 8 rooms Bronze Coins 3600/1200 will be in 3 rooms Total rooms will be (15+8+3) = 26 rooms.
प्र: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5779 05b5cc6bae4d2b4197774d7f8
5b5cc6bae4d2b4197774d7f8- 1264true
- 2220false
- 3241false
- 4Nonefalse
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उत्तर : 1. "264"
व्याख्या :
Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264
प्र: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5768 05b5cc74ae4d2b4197774fa68
5b5cc74ae4d2b4197774fa68- 120 kmfalse
- 216 kmfalse
- 314 kmfalse
- 410 kmtrue
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उत्तर : 4. "10 km"
व्याख्या :
Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.
प्र: The market price of an article was 40% more than its cost price. Rana was going to sell it at market price to a customer, but he showed Rana some defects in the article, due to which Rana gave him a discount of 28.57%. Next day he came again and showed Rana some more defects, hence he gave him another discount that was equal to 12.5% of the cost price. What was the approximate profit/loss to Rana ? 5724 05b5cc75ce4d2b4197774fc8e
5b5cc75ce4d2b4197774fc8e- 1Loss of 12.5%true
- 2Profit of 12.5%false
- 3Loss of 24.5%false
- 4Profit of 22.5%false
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उत्तर : 1. "Loss of 12.5%"
व्याख्या :
Answer: A) Loss of 12.5% Explanation: Let the cost price be Rs. 100Then, market price is Rs. 140Now, the first discount is of 28.57% Rs.140 =~ Rs. 40Hence, its selling price = 140 - 40 = Rs. 100Now since Rana is selling at cost price, any further discount will be equal to loss percentage. The next dicount of 12.5% will be the loss percentage to Rana.
प्र: एक व्यापारी ने 5000 रूपयें प्रति वस्तु की दर से दो वस्तुएँ बेच दी। एक वस्तु को वह 20 प्रतिशत की हानि पर तथा दूसरी वस्तु को 20 प्रतिशत के लाभ पर बेच देता है। पूरे सौदे में उसे कितने प्रतिशत का लाभ या हानि की प्राप्ति हुयी- 5679 05d13414c40daee3c552fcb44
5d13414c40daee3c552fcb44- 14 % लाभfalse
- 24% हानिtrue
- 320% लाभfalse
- 4न तो लाभ न हानिfalse
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उत्तर : 2. "4% हानि"
प्र: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ? 5603 05b5cc6e1e4d2b4197774ebd9
5b5cc6e1e4d2b4197774ebd9- 1Rs. 1100false
- 2Rs. 500true
- 3Rs. 1200false
- 4Rs. 700false
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उत्तर : 2. "Rs. 500"
व्याख्या :
Answer: B) Rs. 500 Explanation: Let the amounts to be received by P, Q and R be p, q and r.p + q + r = 1200p = 1/2 (q + r) => 2p = q + r Adding 'p' both sides, 3p = p + q + r = 1200=> p = Rs.400 q = 1/3 (p + r) => 3q = p + r Adding 'q' both sides, 4q = p + q + r = 1200=> q = Rs.300 r = 1200 - (p + q) => r = Rs.500.
प्र: Find the missing number? 5 19 49 101 181 295 ? 5595 05b5cc6abe4d2b4197774cff2
5b5cc6abe4d2b4197774cff2- 1401false
- 2351false
- 3449true
- 4501false
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उत्तर : 3. "449"
व्याख्या :
Answer: C) 449 Explanation: Given number series is 5 19 49 101 181 295 ? Here the series follows pattern that 5 19 49 101 181 295 ? 14 30 52 80 114 (difference) 16 22 28 34 (difference) 6 6 6 (Common difference) Therefore, the missing number in the series is ? = 295 + 115 + 34 + 6 = 449.
प्र: एक स्कूल में छात्रों की कुल संख्या 3250 है। यदि उस स्कूल में लड़कियों की संख्या 1495 है, तो लड़कों की कुल संख्या का लड़कियों की कुल संख्या से क्रमशः कितना अनुपात है? 5586 15d1b076a8a754124194a7521
5d1b076a8a754124194a7521- 123:27false
- 225:29false
- 327:23true
- 429:25false
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