Examsbook | Hand picked material and question banks

Latest Popular RatedShowing Page 13 of 159Total Questions 1267 Join Examsbook

Q: In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type ? 5579 0

Answer : 1. "26"
Explanation :
Answer: A) 26 Explanation: Gold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600 Find a number which exactly divide all these numbers That is HCF of 18000, 9600& 3600 All the value has 00 at end so the factor will also have 00. HCF for 180, 96 & 36. Factors of 180 = 3 x 3 x 5 x 2 x 2 96 = 2 x 2 x 2 x 2 x 2 x 3 36 = 2 x 2 x 3 x 3 Common factors are 2x2×3=12 Therefore, Actual HCF is 1200 Gold Coins 18000/1200 will be in 15 rooms Silver Coins 9600/1200 will be in 8 rooms Bronze Coins 3600/1200 will be in 3 rooms Total rooms will be (15+8+3) = 26 rooms.

Q: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5564 0

Answer : 1. "264"
Explanation :
Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264

Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5535 0

Answer : 4. "10 km"
Explanation :
Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.

Q: The market price of an article was 40% more than its cost price. Rana was going to sell it at market price to a customer, but he showed Rana some defects in the article, due to which Rana gave him a discount of 28.57%. Next day he came again and showed Rana some more defects, hence he gave him another discount that was equal to 12.5% of the cost price. What was the approximate profit/loss to Rana ? 5495 0

Answer : 1. "Loss of 12.5%"
Explanation :
Answer: A) Loss of 12.5% Explanation: Let the cost price be Rs. 100Then, market price is Rs. 140Now, the first discount is of 28.57% Rs.140 =~ Rs. 40Hence, its selling price = 140 - 40 = Rs. 100Now since Rana is selling at cost price, any further discount will be equal to loss percentage. The next dicount of 12.5% will be the loss percentage to Rana.

Q: Find the missing number? 5 19 49 101 181 295 ? 5456 0

Answer : 3. "449"
Explanation :
Answer: C) 449 Explanation: Given number series is 5 19 49 101 181 295 ? Here the series follows pattern that 5 19 49 101 181 295 ? 14 30 52 80 114 (difference) 16 22 28 34 (difference) 6 6 6 (Common difference) Therefore, the missing number in the series is ? = 295 + 115 + 34 + 6 = 449.

Q: एक व्यापारी ने 5000 रूपयें प्रति वस्तु की दर से दो वस्तुएँ बेच दी। एक वस्तु को वह 20 प्रतिशत की हानि पर तथा दूसरी वस्तु को 20 प्रतिशत के लाभ पर बेच देता है। पूरे सौदे में उसे कितने प्रतिशत का लाभ या हानि की प्राप्ति हुयी- 5449 0

Answer : 2. "4% हानि"

Q: एक स्कूल में छात्रों की कुल संख्या 3250 है। यदि उस स्कूल में लड़कियों की संख्या 1495 है, तो लड़कों की कुल संख्या का लड़कियों की कुल संख्या से क्रमशः कितना अनुपात है? 5436 1

Answer : 3. "27:23"

Q: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ? 5391 0

Answer : 2. "Rs. 500"
Explanation :
Answer: B) Rs. 500 Explanation: Let the amounts to be received by P, Q and R be p, q and r.p + q + r = 1200p = 1/2 (q + r) => 2p = q + r Adding 'p' both sides, 3p = p + q + r = 1200=> p = Rs.400 q = 1/3 (p + r) => 3q = p + r Adding 'q' both sides, 4q = p + q + r = 1200=> q = Rs.300 r = 1200 - (p + q) => r = Rs.500.

Q: In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type ? 5579 0

Q: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5564 0

Answer : 1. "264"
Explanation :
Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264

Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5535 0

Answer : 4. "10 km"
Explanation :
Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.

Q: Find the missing number? 5 19 49 101 181 295 ? 5456 0

Answer : 2. "4% हानि"

Answer : 3. "27:23"

Q: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ? 5391 0

Report Error

Report Error

Report Error

Report Error

Report Error

Report Error

Report Error

Report Error

Q: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5564 05b5cc6bae4d2b4197774d7f8

Answer : 1. "264" Explanation :Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264

Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5535 05b5cc74ae4d2b4197774fa68

Answer : 4. "10 km" Explanation :Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.

Q: Find the missing number? 5 19 49 101 181 295 ? 5456 05b5cc6abe4d2b4197774cff2

Answer : 2. "4% हानि"

Answer : 3. "27:23"

Q: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ? 5391 05b5cc6e1e4d2b4197774ebd9

Report Error

Report Error

Report Error

Report Error

Report Error

Report Error

Report Error

Report Error

Q: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5564 0

Answer : 1. "264"
Explanation :
Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264

Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5535 0

Answer : 4. "10 km"
Explanation :
Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.

Q: Find the missing number? 5 19 49 101 181 295 ? 5456 0

Q: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ? 5391 0