Quantitative Aptitude Practice Question and Answer
8Q: A, B and C started a business where their initial capital was in the ratio of 2:3:4. At the end of 6 months, A invested an amount such that his total capital became equal to C's initial capital investment. If the annual profit of B is Rs. 3000 then what is the total profit ? 1734 05b5cc6c4e4d2b4197774dcfb
5b5cc6c4e4d2b4197774dcfb- 1Rs. 8,640false
- 2Rs. 9,850false
- 3Rs. 10,000true
- 4Rs. 11,220false
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Answer : 3. "Rs. 10,000"
Explanation :
Answer: C) Rs. 10,000 Explanation: Ratio of investments of A, B & C = 2×6+4×6 : 3×12 : 4×12 = 36 : 36 : 48 = 6 : 6 : 8 But given that the annual profit of B is Rs. 3000 => 6 ratio = 3000 Then for the total annual profit of partners is 20 ratio = 3000 x 20/6 = 10,000.
Q: What is 15 as a decimal? 1732 05b5cc6aae4d2b4197774cf8e
5b5cc6aae4d2b4197774cf8e- 10.333false
- 20.666false
- 30.200true
- 40.452false
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Answer : 3. "0.200"
Explanation :
Answer: C) 0.200 Explanation: Here I converted the original fraction to a fraction with the denominator being 10, because decimals can be written in the tenths place. Divide numerator and denominator with '2'15 x 22 = 210 = 0.2
Q: A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be 1731 05b5cc695e4d2b4197774c4ec
5b5cc695e4d2b4197774c4ec- 1Rs. 387false
- 2Rs. 441true
- 3Rs. 469false
- 4Rs. 503false
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Answer : 2. "Rs. 441"
Explanation :
Answer: B) Rs. 441 Explanation: Given principal amount = Rs. 8000 Time = 3yrs Rate = 5% C.I for 3 yrs = 8000 x 105100 x 105100 x 105100 - 8000= Rs. 1261 Now, C.I for 2 yrs = 8000 x 105100 x 105100= Rs. 820 Hence, the required difference in C.I is 1261 - 820 = Rs. 441
Q: A Tank is normally filled in 9 hours but takes four hours longer to fill because of a leak in its bottom. If the tank is full, the leak will empty it in ? 1731 05b5cc6d4e4d2b4197774e5b1
5b5cc6d4e4d2b4197774e5b1- 132.5 hrsfalse
- 229.25 hrstrue
- 330.30 hrsfalse
- 431 hrsfalse
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Answer : 2. "29.25 hrs"
Explanation :
Answer: B) 29.25 hrs Explanation: Let the leak will empty the tank in x hrs Then, 1/9 - 1/x = 1/13 x = 29.25 hrs
Q: Sreya bought a plot for Rs. 6,00,000, then sold half of the plot at 10 % profit and rest at 15% profit. What is the total profit % that Sreya gain? 1725 05b5cc6bfe4d2b4197774da65
5b5cc6bfe4d2b4197774da65- 113.8 %false
- 211.4 %false
- 312.5 %true
- 414.5 %false
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Answer : 3. "12.5 %"
Explanation :
Answer: C) 12.5 % Explanation: 10% profit at half plot = 600000/2 x 10/100 = Rs. 30,000 15% profit at remaining half plot = 600000/2 x 15/100 = Rs. 45,000 Now, total profit = 30000 + 45000 = 75000 Profit % = 75000/600000 x 100 = 12.5 %
Q: The price of a car is increased by 25%, by how much percent, must the new price of this car be decreased to restore its original price ? 1724 05b5cc6c5e4d2b4197774dda0
5b5cc6c5e4d2b4197774dda0- 120%true
- 224%false
- 321%false
- 425%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Suppose that the original price of the car = Rs. x Then new price of the car => (x) + (x ×25/100) = Rs. 5x/4 To restore the original price, the new price must be decreased by 5x/4 − x = x/4 So required percentage =(x/4)/(5x/4) × 100% = 20%
Q: A duster is of dimension 5x5x7 all in cms, is sinked into a cylindrical vessel of radius 5 cm and height 10 cm. After insertion the level of the water is inccresed by 2.14 cm. Then by what percentage the part of the duster is above the layer ? 1721 05b5cc705e4d2b4197774f216
5b5cc705e4d2b4197774f216- 196 %false
- 24 %true
- 397 %false
- 43 %false
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Answer : 2. "4 %"
Explanation :
Answer: B) 4 % Explanation: Imension of the duster is assumed as 5x5x7 cm3 Volume of the duster below the water layer= volume of water increased= πxrxrxh = 3.14×52×2.14 ≈ 168 cm3 Total volume of the duster = 5×5×7 = 175 cm3 Percentage of the duster part below the layer = 168×100/175 = 96% Percentage of the duster part above the layer = 4%
Q: A goods truck travels from a place at a certain time and at fixed speed. After 6hrs another truck leaves the same place and move in same direction of uniform speed of 90kmph. The truck catches up the goods truck in 4hrs. Find the speed of the goods truck ? 1718 05b5cc745e4d2b4197774f9fe
5b5cc745e4d2b4197774f9fe- 136 kmphtrue
- 232 kmphfalse
- 328 kmphfalse
- 434 kmphfalse
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Answer : 1. "36 kmph"
Explanation :
Answer: A) 36 kmph Explanation: Let the speed of goods truck be 'p' kmphDistance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs. 10p = 4 x 90p = 36kmph.Therefore, the speed of the goods truck is p = 36 kmph.