Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: In how many ways the letters of the word 'DESIGN' can be arranged so that no consonant appears at either of the two ends? 1276 05b5cc7b4e4d2b41977750892
5b5cc7b4e4d2b41977750892- 1240false
- 272false
- 348true
- 436false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "48"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 48 Explanation: DESIGN = 6 letters ┬а No consonants appear┬аat either of the two ends.┬а =┬а2┬аx┬а4P4┬а= ┬а2 x 4 x 3 x 2 x 1= ┬а48
рдкреНрд░: How many words can be formed┬аwith or without meaning by using three letters out of k, l, m, n, o without repetition of alphabets. 1276 05b5cc6abe4d2b4197774d058
5b5cc6abe4d2b4197774d058- 160true
- 2120false
- 3240false
- 430false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "60"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 60 Explanation: Given letters are k, l, m, n, o = 5 number of letters to be in the words = 3 Total number of words that can be formed from these 5 letters taken 3 at a time without repetation of letters =┬а5P3┬аways. тЗТ┬а5P3┬а=┬а5┬аx┬а4┬аx┬а3┬а=┬а60┬аwords.
рдкреНрд░: A number is 2 more than thrice the second number and 4 times the smaller number is 5 more than the greater number. What is greater number ┬а? 1276 05b5cc6c9e4d2b4197774df9c
5b5cc6c9e4d2b4197774df9c- 17false
- 223true
- 39false
- 421false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "23"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 23 Explanation: Let the greater and smaller number be p and q respectively. 4q = p + 5 ------ (I) p = 3q+2 ------- (II) From equation (I) and (II) q = 7 p = 23
рдкреНрд░: A contractor undertake to finish a certain work in 124 days and employed 120 men. After 64 days, he found that he had already done 2/3 of the work. How many men can be discharged so that the work may finish in time ? 1274 05b5cc6cce4d2b4197774e16c
5b5cc6cce4d2b4197774e16c- 164false
- 262false
- 358false
- 456true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "56"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 56 Explanation: Days remaining 124 тАУ 64 = 60 days Remaining work = 1 - 2/3 = 1/3 Let men required men for working remaining days be 'm' So men required = (120 x 64)/2 = (m x 60)/1 => m = 64 Men discharge = 120 тАУ 64 = 56 men.
рдкреНрд░: 3/4 divided by 2 is 1271 05b5cc666e4d2b4197774bed0
5b5cc666e4d2b4197774bed0- 13/2false
- 22/3false
- 38/3false
- 43/8true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "3/8"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 3/8 Explanation: 3/4 divided by 2 = 3/4/2 = 3/4x2 = 3/8. ┬а Hence,┬а3/4 divided by 2 is equal to 3/8.
рдкреНрд░: In How many ways can the letters of the word 'CAPITAL' be arranged in such a way that all the vowels always come together? 1270 05b5cc7b4e4d2b41977750897
5b5cc7b4e4d2b41977750897- 1360true
- 2720false
- 3120false
- 4840false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "360"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 360 Explanation: CAPITAL = 7 ┬а Vowels = 3 (A, I, A) ┬а Consonants = (C, P, T, L) ┬а 5 letters which can be arranged in┬а┬а5P5=5! ┬а Vowels A,I =┬а3!2! ┬а No.of arrangements = 5! x┬а3!2!=360
рдкреНрд░: The price of 2 oranges, 3 bananas and 4 apples is Rs. 15. The price of 3 oranges, 2 bananas and 1 apple is Rs. 10. What will be price of 4 oranges, 4 bananas and 4 apples ┬а? 1269 05b5cc6c9e4d2b4197774df5a
5b5cc6c9e4d2b4197774df5a- 1Rs. 10false
- 2Rs. 15false
- 3Rs. 20true
- 4Rs. 25false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "Rs. 20"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) Rs. 20 Explanation: Let the Oranges be 'O', Bananas be 'B' and Apples be 'A' From the given data, ┬а 2O + 3B + 4A = 15 ...... (I) 3O + 2B + A = 10 ..... (II) On adding (I) and (II), 5O + 5B + 5A = 25 O + B + A = 5 4O + 4B + 4A = 20.
рдкреНрд░: Consider 5 independent BernoulliтАЩs trials each with probability of success p. If the probability of at least one failure is greater than or equal to 31/32 , then p lies in the interval ? 1268 05b5cc71ee4d2b4197774f5c7
5b5cc71ee4d2b4197774f5c7- 1[1, 32]false
- 2(0, 1)false
- 3[1, 1/2]true
- 4(1, 1/2]false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "[1, 1/2]"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) [1, 1/2] Explanation: Probability of atleast one failure= 1 - no failure >┬а31/32= 1 - P5┬а>┬а31/32= ┬аP5<1/32= p <┬а1/2Also p >┬а0Hence p lies in [0,1/2].

