Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ

рдкреНрд░: A jeep travels a certain distance taking 6 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 4 hrs. What is the distance travelled by the jeep is ? 1586 0

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    244 km
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    144 km
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    444 km
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    344 km
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рдЙрддреНрддрд░ : 2. "144 km"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 144 km Explanation: Given a jeep travels a certain distance taking 6 hrs in forward journeyDuring the return journey, it takes 4 hrs with an increased speed 12 km/hrLet 'x' be the distance.Now, speed is given by distance/time.Here the difference between both speeds = 12 ┬аx4┬а-┬аx6┬а=┬а12 ┬а3x┬а-┬а2x12┬а=┬а12 ┬а => x = 144 km ┬а Therefore, the distance travelled by the jeep in forward or return journey is x = 144 km.

рдкреНрд░: How many meshes are there in 1 squrare meter of wire gauge if each mesh is 8mm long and 5mm wide ? 1685 0

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    2500
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    25000
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    12500
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    15400
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рдЙрддреНрддрд░ : 2. "25000"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 25000 Explanation: We know that, ┬а One square meter is equal to 10,00,000 sq mm.Given, each mesh is 8mm length and 5mm wideTherefore for each mesh : 8 x 5 = 40 sq mm.So, number of meshes = 100000040┬а= 25000.

рдкреНрд░: How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 ft long and 4 ft wide ? 1677 0

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    9216
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    10246
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    12345
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    7527
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рдЙрддреНрддрд░ : 1. "9216"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 9216 Explanation: It takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch. In a rectangle that is 48 inches by 48 inches, there are 2304 square inches.(1 ft = 12 inches) Since it takes 4 little squares to cover 1 sq inch, then it would need 2304 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 4 feet. That is 9,216 of those squares.

рдкреНрд░: K men agree to donate a gift of Rs. L to trust. If three men drop out how much more will each have to contribute towards the purchase of the gift ? 1377 0

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    L / (k-3)
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    k / (L-3)
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    2K / 3L-K
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    3L / K(K-3)
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рдЙрддреНрддрд░ : 4. "3L / K(K-3)"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) 3L / K(K-3) Explanation: Intial contribution = L/KAfter 3 men drop, then contribution =L/K-3The amount more to pay in contribution =┬аLK-3┬а-┬аLK ┬а =┬а3LK(K-3)

рдкреНрд░: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? 3375 0

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    145
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    165
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    175
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    135
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рдЙрддреНрддрд░ : 3. "175"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 175 Explanation: Given that, ┬аworking days = 5 ┬аworking hours = 8 ┬аA man get rupess per hour is Rs.2.40 ┬аSo in one day the man get total rupees is 2.40 x 8 = 19.2 ┬аSo in 5 days week the man get total rupees is 19.2 x 5 = 96 ┬аSo in 4 week the man get total rupees is 96 x 4 = 384 ┬аSo the man worked for = 160hours in 4 weeks ┬а ┬аBut given that the man earned Rs.432 ┬а ┬аHence remaning money is (432-384 = 48)which is earn by doing overtime work ┬а Overtime hours┬а = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.

рдкреНрд░: Two candidates fought in a municipality election. One of them got 54% of the total votes pooled and won by 1080 votes. What was the total number of votes polled ? 1408 0

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    12000
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    13500
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    15400
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    11000
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рдЙрддреНрддрд░ : 2. "13500"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 13500 Explanation: Given in municipality election 54% votes have won by 1080 ┬а Let the total number of votes be x. ┬а ┬а54x100┬а-┬а46x100┬а=┬а1080 ┬а 8x = 108000 ┬а x = 13,500 ┬а Therefore, total number of votes = 13,500.

рдкреНрд░: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3894 0

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    75 min
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    82 min
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    90 min
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    101 min
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рдЙрддреНрддрд░ : 3. "90 min"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.

рдкреНрд░: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 1959 0

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    79
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    77
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    76
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    73
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рдЙрддреНрддрд░ : 1. "79"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.

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    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
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    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
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    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
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    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
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    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

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    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ