Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ? 1430 05b5cc741e4d2b4197774f9d6
5b5cc741e4d2b4197774f9d6- 16/19false
- 23/10true
- 37/10false
- 46/17false
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उत्तर : 2. "3/10"
व्याख्या :
Answer: B) 3/10 Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20Let E = event of getting a multiple of 4 or 15 =multiples od 4 are {4, 8, 12, 16, 20}And multiples of 15 means multiples of 3 and 5= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.= the common multiple is only (15).=> E = n(E)= 6Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.
प्र: Rs. 7444 is divided among 5 ladies, 3 gents and 3 girls. The ratio of share of a lady, a gents and a girl is 7: 4: 3. What is the share of gents ? 3561 05b5cc741e4d2b4197774f9cc
5b5cc741e4d2b4197774f9cc- 1Rs. 1595.14true
- 2Rs. 1793.4false
- 3Rs. 595.14false
- 4Rs. 1551.5false
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उत्तर : 1. "Rs. 1595.14"
व्याख्या :
Answer: A) Rs. 1595.14 Explanation: Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3No of ladies, gents and girls are 5, 3, 3Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9so part of gents = (12/56) x 7444 = Rs. 1595.142so part of 1 gents = 1595.142/3 = Rs. 531.71.
प्र: The ages of Anushka, Kajal and Charu latha together are 57 years. Bharti is thrice as old as Anushka and Charu latha is 12 years older than Anushka. Then, the respective age of Anushka, Kajal and Charu latha is ? 3446 05b5cc741e4d2b4197774f9b8
5b5cc741e4d2b4197774f9b8- 127, 9, 21false
- 29, 21, 27false
- 321, 27, 9false
- 49, 27, 21true
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उत्तर : 4. "9, 27, 21"
व्याख्या :
Answer: D) 9, 27, 21 Explanation: Let Anushka age = XCharu latha 12 yrs older than Anushka so Charu latha age = x+12Kajal is thrice as old as Anushka so Kajal age = 3xThe ages of Anushka, Kajal and Charu latha together are 57 yearsi.e x + (x+12) + 3x = 57=> 5x = 45:- x = 9Anushka age = 9Kajal age = 3x = 27Charu latha age = x+12 = 21
प्र: When a number is divided by 138 the remainder is 26. What will be the remainder if the same number is divided by 23 ? 1499 05b5cc741e4d2b4197774f9b3
5b5cc741e4d2b4197774f9b3- 14false
- 26false
- 33true
- 41false
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उत्तर : 3. "3"
व्याख्या :
Answer: C) 3 Explanation: Number = quotient x divisor + remainder;so, herenumber = 138 k + 26=> (23 x 6k) + (23+3)=> 23(6k+1)+3so, remainder is 3.
प्र: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 3159 05b5cc741e4d2b4197774f9a9
5b5cc741e4d2b4197774f9a9- 1Rs. 1100false
- 2Rs. 1793.4false
- 3Rs. 1440false
- 4Rs. 1232true
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उत्तर : 4. "Rs. 1232"
व्याख्या :
Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232
प्र: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 2183 05b5cc741e4d2b4197774f9a4
5b5cc741e4d2b4197774f9a4- 114false
- 216false
- 312false
- 415true
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उत्तर : 4. "15"
व्याख्या :
Answer: D) 15 Explanation: Let 'K' be the total number of sweets.Given total number of students = 112If sweets are distributed among 112 children,Let number of sweets each student gets = 'L' => K/112 = L ....(1)But on that day students absent = 32 => remaining = 112 - 32 = 80Then, each student gets '6' sweets extra. => K/80 = L + 6 ....(2)from (1) K = 112L substitute in (2), we get112L = 80L + 48032L = 480L = 15 Therefore, 15 sweets were each student originally supposed to get.
प्र: A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ? 4504 05b5cc741e4d2b4197774f99f
5b5cc741e4d2b4197774f99f- 1400false
- 2600false
- 3900true
- 4700false
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उत्तर : 3. "900"
व्याख्या :
Answer: C) 900 Explanation: 6,400 gents, 2400 ladies in that company.So total 8,800employees.for 8,800 employees, we want 2400 ladies.for 12,100employees we want how many ladies ?=> (12,100/8,800) x 2400 = 3300.So we want 3300 - 2400 = 900 more ladies.
प्र: A secret can be told to only 3 persons in 3 minutes. Each person in turn tells 3 other persons in the next 3 minutes and the processes continues accordingly. In 30 minutes how many persons can be told this secret in this way ? 2719 05b5cc741e4d2b4197774f99a
5b5cc741e4d2b4197774f99a- 188572true
- 277854false
- 399584false
- 455654false
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उत्तर : 1. "88572"
व्याख्या :
Answer: A) 88572 Explanation: Given a secret is told to 3 persons in 3 minutes.And if the process continues with each person saying 3 other persons,In 30 minutes => the rocess for 10 times because each person time is 3 minutes.Required number of persons = 3 + 32 + 33 + .... + 39 + 310 Now it forms a geometric progression, Sum to n terms is S = arn - 1r - 1 Here a = 3, r = 3 => 59048 x 3 /2 = 88572.

