Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: The concentration of glucose in three different mixtures (glucose and alcohol) is 12,35 and 45 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture? 2804 0

  • 1
    3:2
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  • 2
    4:3
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  • 3
    2:3
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  • 4
    3:4
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उत्तर : 1. "3:2"
व्याख्या :

Answer: A) 3:2 Explanation: Concentration of glucose are in the ratio = 12:35:45 Quantity of glucose taken from A = 1 liter out of 2 Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit Quantity of glucose taken from C = 0.8 lit So, total quantity of glucose taken from A,B and C = 3.6 lit So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit Ratio of glucose to alcohol = 3.6/2.4 = 3:2

प्र: The calendar for the year 2018 will be the same for the year 2787 0

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    2023
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  • 2
    2027
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  • 3
    2029
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  • 4
    2022
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उत्तर : 3. "2029"
व्याख्या :

Answer: C) 2029 Explanation: How to find the years which have the same Calendars :   Leap year calendar repeats every 28 years. Here 28 is distributed as 6 + 11 + 11.   Rules: a) If given year is at 1st position after Leap year then next repeated calendar year is Givenyear+6. b) If given year is at 2nd position after Leap year then next repeated calendar year is Givenyear+11. c) If given year is at 3rd position after Leap year then next repeated calendar year is Givenyear+11.   Now, the given year is 2018 We know that 2016 is a Leap year. 2016    2017    2018    2019  2020 Lp Y      1st     2nd      3rd     Lp Y   Here 2018 is at 2 nd position after the Leap year. According to rule b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.

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उत्तर : 3. "12 मिनट"

प्र: How many prime numbers exist in 65×359×113 ? 2781 0

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    29
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  • 2
    31
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  • 3
    33
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  • 4
    27
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उत्तर : 2. "31"
व्याख्या :

Answer: B) 31 Explanation: Given  65×359×113 ⇒2×35×5×79×113  ⇒25×35×59×79×113 Thus, there are (5 + 5 + 9 + 9 + 3)= 31 prime numbers.

प्र: Srinivas bought 10 cycles for Rs. 1,750 each. He sold 4 cycles for Rs 8,400, 3 for Rs 1900 each . At what price should he sell the remaining cycles so as to earn an average profit of Rs 320 per cycle ? 2751 0

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    Rs. 1580
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  • 2
    Rs. 2200
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  • 3
    Rs. 1785
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  • 4
    Rs. 1950
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उत्तर : 2. "Rs. 2200"
व्याख्या :

Answer: B) Rs. 2200 Explanation: He sold 4 cycles for Rs. 8400[It means each cycle price is Rs. 2100]And again he sold 3 cycles for Rs. 1900 eachIf he want to gain avg profit on each cycle is Rs. 320 per cycle.So profit for 10 cycles is @ Rs.320 is,10 x 320 = Rs. 3200He already got Rs. 1850 profit by selling 7 cycles.Now, remaining amount is 3200 - 1850 = 1350So from remaining 3 cycles we want to get Rs. 1350 profit ,1350/3 = 450so he must sell remaining 3 cycles at Rs. 2200 each one.

प्र: A man can row against the current three fourth of a kilometer in 15 min and returns same distance in 10 min, then ratio of his speed to that of current? 2750 0

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    5:1
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  • 2
    3:1
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  • 3
    4:1
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  • 4
    2:1
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उत्तर : 1. "5:1"
व्याख्या :

Answer: A) 5:1 Explanation: Let the speed of the man in still water = p kmph Speed of the current = s kmph Now, according to the questions (p + s) x 10 = (p - s) x 15 2p + 2s = 3p - 3s => p : s = 5 : 1   Hence, ratio of his speed to that of current = 5:1.

प्र:

निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आना चाहिए?

105.003+307.993+ 215.630=?

2744 0

  • 1
    610
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  • 2
    650
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  • 3
    660
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  • 4
    670
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  • 5
    630
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उत्तर : 5. "630"
व्याख्या :

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प्र: There are 44 students in a hostel, due to the administration,  15 new students has joined. The expense of the mess increase by Rs. 33 per day. While the average expenditure per head diminished by Rs. 3, what was the original expenditure of the mess ? 2742 0

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    Rs. 404
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  • 2
    Rs. 514
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  • 3
    Rs. 340
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  • 4
    Rs. 616
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उत्तर : 4. "Rs. 616"
व्याख्या :

Answer: D) Rs. 616 Explanation: Let the average expenditure per head be Rs. pNow, the expenditure of the mess for old students is Rs. 44pAfter joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33Therefore, 59(p-3) = 44p + 3359p - 177 = 44p + 3315p = 210 => p = 14Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.

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