Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number ? 1557 0

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    17
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  • 2
    19
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  • 3
    13
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  • 4
    11
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उत्तर : 3. "13"
व्याख्या :

Answer: C) 13 Explanation: (385/1001) = 5/13 First Number is 5 => Fourth number is 13

प्र: A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ? 1353 0

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    28 kmph
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  • 2
    24 kmph
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  • 3
    26 kmph
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  • 4
    32 kmph
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उत्तर : 2. "24 kmph"
व्याख्या :

Answer: B) 24 kmph Explanation: Total time taken = k/40 + 2k/20 hours = 5k/40 = k/8 hours Average speed = 3k/(k/8) = 24 kmph.

प्र: An automobile financier claims to be lending money at S.I., but he includes the interest every six months for calculating the principal. If he is charging an interest of 8%, the effective rate of interest becomes ? 1205 0

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    10.25 %
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  • 2
    8.16 %
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  • 3
    9.63 %
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  • 4
    0.16 %
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उत्तर : 2. "8.16 %"
व्याख्या :

Answer: B) 8.16 % Explanation: Let the sum be Rs. 100. Then,S.I. for first 6 months = (100 x 8 x 1) / (100 x 2) = Rs. 4S.I. for last 6 months = (104 x 8 x 1) / (100 x 2) = Rs. 4.16So, amount at the end of 1 year = (100 + 4 + 4.16) = Rs. 108.16Effective rate = (108.16 - 100) = 8.16%.

प्र: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3034 0

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    5:3
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  • 2
    1:4
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  • 3
    4:1
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  • 4
    9:1
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उत्तर : 4. "9:1"
व्याख्या :

Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters   If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.   Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters   10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.   The ratio of milk and water in the new mixture = 16:4 = 4:1   If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters.   Amount of water removed = 2 liters.   Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters.   Now 10 lts milk is added => total milk = 18 lts   The required ratio of milk and water in the final mixture obtained   = (8 + 10):2 = 18:2 = 9:1.

प्र: The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number  ? 1266 0

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    270
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  • 2
    1270
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  • 3
    350
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  • 4
    720
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उत्तर : 1. "270"
व्याख्या :

Answer: A) 270 Explanation: Let the smallest number be x.Then larger number = (x + 1365)x + 1365 = 6x + 15= 5x = 1350 x = 270Smaller number = 270.

प्र: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%   ? 1945 0

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    30 %
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  • 2
    25 %
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  • 3
    15 %
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  • 4
    20 %
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उत्तर : 4. "20 %"
व्याख्या :

Answer: D) 20 % Explanation: SP2 = 2/3 SP1CP = 100SP2 = 802/3 SP1 = 80 SP1 = 120100 --- 20   => 20%

प्र: A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in  ? 1508 0

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    8 hrs
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    12 hrs
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  • 3
    6 hrs
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  • 4
    4 hrs
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उत्तर : 3. "6 hrs"
व्याख्या :

Answer: C) 6 hrs Explanation: Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.  Then, (1/x + 2/x + 3/x) = 1/2  => 6/x = 1/2      => x = 12  So, B takes 6 hours to finish the work.

प्र: In how many years, Rs. 200 will produce the same interest @ 5 % as Rs. 900 produce in 2 years @ 3 ½ %  ? 4335 0

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    5.2 yrs
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  • 2
    7 yrs
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  • 3
    7.9 yrs
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  • 4
    6.3 yrs
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उत्तर : 4. "6.3 yrs"
व्याख्या :

Answer: D) 6.3 yrs Explanation: P = Rs. 900, R = 3 ½ % = 7/2 %, T = 2 years.  Therefore,  S.I. = PTR/100 S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63 Now, P = Rs. 200, S.I. = Rs. 63, R = 5 % Time = ((100 x 63) / (200 x 5) ) years = 6.3 years.

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