Quantitative Aptitude Practice Question and Answer

Q: A class has 8 football players. A 5-member team and a captain will be selected out of these 8 players. How many different selections can be made ? 1940 0

  • 1
    210
    Correct
    Wrong
  • 2
    168
    Correct
    Wrong
  • 3
    1260
    Correct
    Wrong
  • 4
    10!/6!
    Correct
    Wrong
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Answer : 2. "168"
Explanation :

Answer: B) 168 Explanation: we can select the 5 member team out of the 8 in 8C5 ways = 56 ways. The captain can be selected from amongst the remaining 3 players in 3 ways. Therefore, total ways the selection of 5 players and a captain can be made = 56x3 = 168 ways.   (or)   Alternatively, A team of 6 members has to be selected from the 8 players. This can be done in 8C6 or 28 ways. Now, the captain can be selected from these 6 players in 6 ways. Therefore, total ways the selection can be made is 28x6 = 168 ways.

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Answer : 3. "80%"
Explanation :

Answer: C) 80% Explanation: circumference of A = 2πr = 8 => so r = 4πvolume = π×4π2×10 = 160πcircumference of B = 2πr   = 10 => so r = 5πvolume = π×5π2×8 =  200πso ratio of capacities = 160/200 = 0.8 so capacity of A will be 80% of the capacity of B.

Q: There are 15 lines in plane. How many intersections (Maximum) can be made ? 1938 0

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    55
    Correct
    Wrong
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    105
    Correct
    Wrong
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    215
    Correct
    Wrong
  • 4
    148
    Correct
    Wrong
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Answer : 2. "105"
Explanation :

Answer: B) 105 Explanation: First line will cut all other 14, similarly second will cut 13, and so onTotal = 14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105.

Q: What is the smallest number by which 2880 must be divided in order to make it into a perfect square ? 1938 0

  • 1
    2
    Correct
    Wrong
  • 2
    3
    Correct
    Wrong
  • 3
    4
    Correct
    Wrong
  • 4
    5
    Correct
    Wrong
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Answer : 4. "5"
Explanation :

Answer: D) 5 Explanation: By trial and error method, we get2880/3 = 960 is not a perfect square2880/4 = 720 is not a perfect square2880/5 = 576 which is perfect square of 24Hence, 5 is the least number by which 2880 must be divided in order to make it into a perfect square.

Q: 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 = ? 1937 0

  • 1
    0
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    12
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 3. "12"
Explanation :

Answer: C) 12 Explanation: Given  1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 Using BODMAS Rule, As multiplication precedes addition, 1 x 0 = 0,  Now, 10 + 0 + 1 + 1 = 10 + 2 = 12.   Hence, 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 = 12.

Q: Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to: 1937 0

  • 1
    596/9
    Correct
    Wrong
  • 2
    605/9
    Correct
    Wrong
  • 3
    645/9
    Correct
    Wrong
  • 4
    700/9
    Correct
    Wrong
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Answer : 4. "700/9"
Explanation :

Answer: D) 700/9 Explanation: Let Veena's weight = 1 kg Sana's weight = 2 kg Sneha's weight = 1.4 kg Rina's weight = 1.8 kg Now,according to the given data in the question, 1.8x100 = 1.4   x = 1.4 × 1001.8 = 7009 = 77 79.

Q: A Committee of 5 persons is to be formed from a group of 6 gentlemen and 4 ladies. In how many ways can this be done if the committee is to be included atleast one lady? 1936 0

  • 1
    123
    Correct
    Wrong
  • 2
    113
    Correct
    Wrong
  • 3
    246
    Correct
    Wrong
  • 4
    945
    Correct
    Wrong
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Answer : 3. "246"
Explanation :

Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking.    (i) 1 lady out of 4 and 4 gentlemen out of 6  (ii) 2 ladies out of 4 and 3 gentlemen out of 6  (iii) 3 ladies out of 4 and 2 gentlemen out of 6  (iv) 4 ladies out of 4 and 1 gentlemen out of 6    In case I the number of ways = C14×C46 = 4 x 15 = 60  In case II the number of ways = C24×C36 = 6 x 20 = 120  In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6    Hence, the required number of ways = 60 + 120 + 60 + 6 = 246

Q: Please enter the Missing number: 4 8 14 22 ? 1934 0

  • 1
    28
    Correct
    Wrong
  • 2
    32
    Correct
    Wrong
  • 3
    46
    Correct
    Wrong
  • 4
    36
    Correct
    Wrong
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Answer : 2. "32"
Explanation :

Answer: B) 32 Explanation: Here the given series follows a pattern that, 22 - 0 = 4   32 - 1 = 8   42 - 2 = 14 52 - 3 = 22 62 - 4 = 32 Hence, the missing number is 32     Method 2 :: The difference between 4 and 8 is 4, the difference between 8 and 14 is 6, the difference between 14 and 22 is 8. So the next difference between 22 and the next number will be 10 since it follows (4,6,8,10 - add +2 each time) Hence, 22 + 10 = 32 is the missing number.

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