Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the odd one out of the series ? 35, 48, 54, 63, 81, 105 1870 05b5cc6dae4d2b4197774e8c3
5b5cc6dae4d2b4197774e8c3- 163false
- 248false
- 335true
- 481false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
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उत्तर : 3. "35"
व्याख्या :
Answer: C) 35 Explanation: 48, 54, 63, 81 and 105 are divisible by 3 but not 35.
प्र: A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely ? 1130 05b5cc6dae4d2b4197774e8be
5b5cc6dae4d2b4197774e8be- 14 hrs 15 minfalse
- 23 hrs 24 minfalse
- 34 hrs 51 minfalse
- 43 hrs 45 mintrue
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 4. "3 hrs 45 min"
व्याख्या :
Answer: D) 3 hrs 45 min Explanation: Time taken by one tap to fill half of the tank = 3 hrs. Part filled by the taps in 1 hour = 4 x 1/6 = 2/3 Remaining part = 1 - 1/2 = 1/2 2/3 : 1/2 :: 1 : p p = 1/2 x 1 x 3/2 = 3/4 hrs. i.e., 45 min So, total time taken = 3 hrs 45 min.
प्र: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is ? 1455 05b5cc6dae4d2b4197774e8a5
5b5cc6dae4d2b4197774e8a5- 145 kmphfalse
- 225 kmphfalse
- 330 kmphfalse
- 450 kmphtrue
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 4. "50 kmph"
व्याख्या :
Answer: D) 50 kmph Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) x (18/5)] km/hr = 45 km/hr. Let the speed of the train be 'S' km/hr. Then, relative speed = (S - 5) km/hr. S - 5 = 45 => S = 50 km/hr.
प्र: A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast ? 11891 05b5cc6dae4d2b4197774e89e
5b5cc6dae4d2b4197774e89e- 17500true
- 26200false
- 35600false
- 44700false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
- SingleChoice
उत्तर : 1. "7500"
व्याख्या :
Answer: A) 7500 Explanation: Let the candidates be A & B35%-----------A65%-----------B Difference of votes (65-35)% = 30% => 30% ------- 2250Then for 100% -------- ? => 7500
प्र: Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m. ? 1452 05b5cc6dae4d2b4197774e899
5b5cc6dae4d2b4197774e899- 120 kmphfalse
- 218 kmphfalse
- 312 kmphtrue
- 416 kmphfalse
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- Workspace
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उत्तर : 3. "12 kmph"
व्याख्या :
Answer: C) 12 kmph Explanation: Let the distance traveled be x km.Then, x/10 - x/15 = 23x - 2x = 60 => x = 60 km.Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.Required speed = 60/5 = 12 kmph.
प्र: Find the Odd one out of the given series 6, 15, 35, 77, 165, 221 11605 05b5cc6d9e4d2b4197774e84d
5b5cc6d9e4d2b4197774e84d- 1221false
- 2165true
- 335false
- 477false
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उत्तर : 2. "165"
व्याख्या :
Answer: B) 165 Explanation: The terms of the series are products of two consecutive prime numbers i.e. (2 x 3), (3 x 5), (5 x 7), (7 x 11),..... So, 165 is wrong and must be replaced by (11 x 13) i.e. 143.
प्र: Express 6.72 % in ratio ? 2013 05b5cc6d9e4d2b4197774e839
5b5cc6d9e4d2b4197774e839- 165 : 124false
- 242 : 625true
- 321 : 125false
- 437 : 442false
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उत्तर : 2. "42 : 625"
व्याख्या :
Answer: B) 42 : 625 Explanation: 6.72/100 = 672/10000 = 42/625
प्र: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1648 05b5cc6d9e4d2b4197774e816
5b5cc6d9e4d2b4197774e816- 130false
- 236false
- 340true
- 442false
- उत्तर देखेंउत्तर छिपाएं
- Workspace
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उत्तर : 3. "40"
व्याख्या :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.