Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey? 1770 05b5cc6ade4d2b4197774d12f
5b5cc6ade4d2b4197774d12f- 132 kmphfalse
- 220 kmphfalse
- 318 kmphfalse
- 424 kmphtrue
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उत्तर : 4. "24 kmph"
व्याख्या :
Answer: D) 24 kmph Explanation: Let the total distance of the journey of a man = d kms Now, the average speed of the entire journey = dd120 + d120 + d40 = 24 kmph.
प्र: Find the odd one in the given series ? 5-20-25, 10-40-50, 4-15-24, 25-100-125 1768 05b5cc6dde4d2b4197774e9ec
5b5cc6dde4d2b4197774e9ec- 14-15-24true
- 25-20-25false
- 310-40-50false
- 425-100-125false
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उत्तर : 1. "4-15-24"
व्याख्या :
Answer: A) 4-15-24 Explanation: In each term second two numbers are multiples of the first number. But in 4-15-24 15 is not multiple of 4.
प्र: If two cards are taken one after another without replacing from a pack of 52 cards. What is the probability for the two cards be Ace ? 1768 05b5cc74ae4d2b4197774fa81
5b5cc74ae4d2b4197774fa81- 151/1221false
- 242/221false
- 31/221true
- 452/1245false
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उत्तर : 3. "1/221"
व्याख्या :
Answer: C) 1/221 Explanation: Total Combination of getting a card from 52 cards = C152 Because there is no replacement, so number of cards after getting first card= 51 Now, Combination of getting an another card= C151 Total combination of getting 2 cards from 52 cards without replacement= (C152×C151) There are total 4 Ace in stack. Combination of getting 1 Ace is = C14 Because there is no replacement, So number of cards after getting first Ace = 3 Combination of getting an another Ace = C13 Total Combination of getting 2 Ace without replacement=C14×C13 Now,Probability of getting 2 cards which are Ace =C14×C13C152×C151 = 1/221.
प्र: With an average speed of 40 km/hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. Find the length of the total journey? 1768 05b5cc662e4d2b4197774be9c
5b5cc662e4d2b4197774be9c- 170 kmstrue
- 260 kmsfalse
- 345 kmsfalse
- 430 kmsfalse
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उत्तर : 1. "70 kms"
व्याख्या :
Answer: A) 70 kms Explanation: Let the time taken by train be 't' hrs. Then, 40t = 35t + 1560 40t = 35t + 35/4 t = 7/4 hrs Therefore, Required length of the total journey d = s x t = 40 x 7/4 = 70 kms.
प्र: Vishal and Raghu jointly started a business. Vishal invested three times as Raghu did and invested his money for double time as compared to Raghu. Raghu earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was ? 1767 05b5cc6dee4d2b4197774ea8f
5b5cc6dee4d2b4197774ea8f- 1Rs. 28,000true
- 2Rs. 18,000false
- 3Rs. 14,000false
- 4Rs. 8,000false
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उत्तर : 1. "Rs. 28,000"
व्याख्या :
Answer: A) Rs. 28,000 Explanation: Investments ratio is = 3:1Time period ratio is = 2:1 As they are proportional to gain ------Gain ratio of Vishal and raghu = 6:1 But given Raghu got Rs. 4000, =? 1 ----- 4000 7 ----- ? => Rs.28,000 The total gain = Rs.28,000
प्र: The price of pulses has increased by 25%. The percentage of reduction that a family should effect in the use of pulses so as not to increase the expenditure on this account is ? 1767 05b5cc75ce4d2b4197774fc3e
5b5cc75ce4d2b4197774fc3e- 116%false
- 220%true
- 384%false
- 472%false
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उत्तर : 2. "20%"
व्याख्या :
Answer: B) 20% Explanation: Reduction in consumption= P100+P X 100%= 25100+25 X 100%= 20%
प्र: K and L start a business jointly. K invests Rs.16000 for 8 months and L remains in the business for 4 months. Out of the total profit L claims 2/7th share. How much money is contributed by L? 1765 05b5cc767e4d2b4197774fe22
5b5cc767e4d2b4197774fe22- 1Rs. 13,204false
- 2Rs. 14,521false
- 3Rs. 12,800true
- 4Rs. 15,000false
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उत्तर : 3. "Rs. 12,800"
व्याख्या :
Answer: C) Rs. 12,800 Explanation: Given share of L is 2/7 th of profit. Then, their profits are divided in to 5:2 ratio. Ratio of K and L is 16000×8x×4=52 x = Rs. 12,800.
प्र: If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ? 1765 05b5cc731e4d2b4197774f7fb
5b5cc731e4d2b4197774f7fb- 16false
- 28false
- 34true
- 49false
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उत्तर : 3. "4"
व्याख्या :
Answer: C) 4 Explanation: N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4