Bank Exams प्रश्न और उत्तर का अभ्यास करें
8प्र: Which must be true for metamorphism to occur? 2169 05b5cc666e4d2b4197774bf21
5b5cc666e4d2b4197774bf21- 1The parent rock must be in solid form.false
- 2Tons of pressure must be applied.false
- 3The process must take place underground.false
- 4All the abovetrue
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उत्तर : 4. "All the above"
व्याख्या :
Answer: D) All the above Explanation: Metamorphism is the change of minerals or geologic texture in pre-existing rocks, without the protolith melting into liquid magma. The change occurs primarily due to heat, pressure, and the introduction of chemically active fluids. The parent rock must be in solid form. Tons of pressure must be applied for metamorphism to happen. The process must take place underground.
प्र: Where is glucose stored in the body? 2169 05b5cc670e4d2b4197774c025
5b5cc670e4d2b4197774c025- 1bonesfalse
- 2bloodtrue
- 3organsfalse
- 4None of the abovefalse
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उत्तर : 2. "blood"
व्याख्या :
Answer: B) blood Explanation: In human body, glucose is stored in blood stream before it is converted to glycogen. Excess glucose is stored in the form of fats. After conversion, glycogen is stored in Muscles and Liver.
प्र: Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ? 2169 05b5cc70be4d2b4197774f2f6
5b5cc70be4d2b4197774f2f6- 160%false
- 240%true
- 350%false
- 430%false
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उत्तर : 2. "40%"
व्याख्या :
Answer: B) 40% Explanation: Lets say shyam sells at 100, Since Ram sells 25% cheaper than Shyam, Therefor Ram sells at less than 25% of100 or 75 rs. Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or 125% of x (say x price of bram )=75rs.or 100% of x =60rs.hence price of bram is 60rs. now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%. Hence Brams Good is 40% cheaper than that of Shyam's good.
प्र: Which value is equal to 5% of 1,500? 2167 05b5cc666e4d2b4197774bee9
5b5cc666e4d2b4197774bee9- 135false
- 255false
- 375true
- 445false
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उत्तर : 3. "75"
व्याख्या :
Answer: C) 75 Explanation: In the question it is asked for 5% of 1500 5 x 1500/100 = 15 x 5 = 75. Hence, 5% of 1,500 is equal to 75.
प्र: Find the odd one out of the following number series? 56, 64, 48, 90, 16, 144 2166 05b5cc658e4d2b4197774bddd
5b5cc658e4d2b4197774bddd- 148false
- 264false
- 390true
- 416false
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उत्तर : 3. "90"
व्याख्या :
Answer: C) 90 Explanation: The given number series follows a pattern that, 56 56 + 8 = 64 64 - 16 = 48 48 + 32 = 80 (Not equal to 90) 80 - 64 = 16 16 + 128 = 144 Hence, the odd number in the given number series is 90.
प्र: The marked price of a Watch is Rs.8400. It is to be sold at Rs.6896 at two successive discounts. If the first discount is 12%, the second discount is ? 2165 05b5cc720e4d2b4197774f627
5b5cc720e4d2b4197774f627- 17.2 %false
- 29.14 %false
- 37.13 %false
- 46.709 %true
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उत्तर : 4. "6.709 %"
व्याख्या :
Answer: D) 6.709 % Explanation: (100-x)% of 88% of 8400 = 6896 => 100-x10088100x8400 = 6896 => x = 6.709%
प्र: A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold? 2165 05b5cc6a7e4d2b4197774cdef
5b5cc6a7e4d2b4197774cdef- 158 lfalse
- 265 lfalse
- 350 ltrue
- 462 lfalse
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उत्तर : 3. "50 l"
व्याख्या :
Answer: C) 50 l Explanation: Let the tin contain 5x litres of liquids 5x - 45 x 455x - 45 x 15 + 45 = 25 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 15 + 45 = 50 litres.
प्र: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 2164 05b5cc701e4d2b4197774f170
5b5cc701e4d2b4197774f170- 1Rs. 1,24,000false
- 2Rs. 1,44,000true
- 3Rs. 1,32,000false
- 4Rs. 1,62,000false
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उत्तर : 2. "Rs. 1,44,000"
व्याख्या :
Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.