Directions : In each of these questions, two equations numbered I and II with variables x and y are given. You have to solve both the equations to find the value of x and y. Give answer:

1) if x>y

2) if x ≥ y

3) if x<y

4) if x ≤ y

5) if x= y or relationship between x and y cannot be determined

प्र:

I. $$ {\sqrt{6}x^{2}}+(4+\sqrt{15})x+2\sqrt{10}=0$$
II. $$ {y^{2}}-(\sqrt{6}+\sqrt{5})y+\sqrt{30}=0$$

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