Practice Question and Answer
8Q: The longest ship canal in the world is the 3988 05b5cc69fe4d2b4197774c9fb
5b5cc69fe4d2b4197774c9fb- 1Suez canal, Egyptfalse
- 2Kiel canal, Germanyfalse
- 3Panama canal, Central Americafalse
- 4St. Laurence Seaway (USA and Canada)true
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Answer : 4. "St. Laurence Seaway (USA and Canada)"
Explanation :
Answer: D) St. Laurence Seaway (USA and Canada) Explanation:
Q: दी गई आकृति में, DE‖BC तथा DE=1/3 BC है। यदि त्रिभुज ADE का क्षेत्रफल 20 cm2 है तो त्रिभुज DEC का क्षेत्रफल क्या है?
3988 05d70d78b9004b376a58c11e4
5d70d78b9004b376a58c11e4- 140true
- 260false
- 380false
- 4120false
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Answer : 1. "40"
Q: A thief steals half the total number of loaves of bread plus 1/2 loaf from a bakery. A second thief steals half the remaining number of loaves plus 1/2 loaf and so on. After the 5th thief has stolen there are no more loaves left in the bakery. What was the total number of loaves did the bakery have at the beginning ? 3987 05b5cc70ee4d2b4197774f33c
5b5cc70ee4d2b4197774f33c- 121false
- 211false
- 317false
- 431true
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Answer : 4. "31"
Explanation :
Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.
Q:Change the following sentence in to Passive/Active voice.
Champagne is drunk on new year’s eve.
3987 05e6b9ae0dc5d481fc65266eb
5e6b9ae0dc5d481fc65266eb- 1They will drink champagne on new year’s eve.false
- 2People drink champagne on new year’s eve.true
- 3People always drink champagne on new year’s eve.false
- 4Let us drink champagne on new year’s eve.false
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Answer : 2. "People drink champagne on new year’s eve. "
Q: यदि If L=+, M= - , N = ×, P=÷ है तो 5 N 5 P 5 L 5 M 5 =? का मान है।
3987 05f0c0a0bcec10557a8da87d3
5f0c0a0bcec10557a8da87d3- 15true
- 20false
- 310false
- 415false
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Answer : 1. "5"
Q: राजस्थान का वह स्थल जो पशुपालन का प्राचीनतम साक्ष्य प्रस्तुत करता है ?
3983 060ed76cb2f19390587395e5d
60ed76cb2f19390587395e5d- 1दरfalse
- 2आहड़false
- 3कालीबंगाfalse
- 4बागोरtrue
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Answer : 4. "बागोर"
Explanation :
जानवरों को पालतू बनाने का सबसे पहला प्रमाण 5500 ईसा पूर्व आदमगढ़ (म.प्र.) और राजस्थान के बागोर से मिलता है। और 4500 ई.पू. क्रमश।
Q: A man has a certain number of small boxes to pack into parcles. If he packs 3, 4, 5 or 6 in a parcel, he is left with one over; if he packs 7 in a parcle, none is left over. What is the number of boxes, he may have to pack? 3983 05b5cc7b9e4d2b4197775095f
5b5cc7b9e4d2b4197775095f- 1106false
- 2301true
- 3309false
- 4400false
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Answer : 2. "301"
Explanation :
Answer: B) 301 Explanation: Clearly, the required number would be such that it leaves a remainder of 1 when divided by 3, 4, 5, or 6 and no remainder when divided by 7. Thus, the number must be of the form (L.C.M of 3, 4, 5, 6) x + 1 i.e., (60x + 1 ) and a multiple of 7. Clearly, for x = 5, the number is a multiple of 7. So the number is 301.
Q: Ten years ago, Kumar was thrice as old as Sailesh was but 10 years hence, he will be only twice as old. Find Kumar’s present age ? 3982 05b5cc77fe4d2b419777501a6
5b5cc77fe4d2b419777501a6- 150 yearsfalse
- 270 yearstrue
- 360 yearsfalse
- 440 yearsfalse
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Answer : 2. "70 years"
Explanation :
Answer: B) 70 years Explanation: Let Kumar’s present age be "x" years and Sailesh’s present age be "y" years.Then, according to the first condition, x - 10 = 3(y - 10) => x - 3y = - 20 ........(1) Now, Kumar’s age after 10 years = (x + 10) years. Sailesh’s age after 10 years = (y + 10) years. (x + 10) = 2 (y + 10) => x - 2y = 10 ......(2) Solving (1) and (2), we get x = 70 and y = 30 Kumar’s present age = 70 years and Sailesh’s present age = 30 years.

